Leetcode: 1295
1295. Find Numbers with Even Number of Digits
Given an array nums of integers, return how many of them contain an even number of digits.
Example 1:
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
Constraints:
- 1 <= nums.length <= 500
- 1 <= nums[i] <= 10^5
Solution:
class Solution {
public int findNumbers(int[] nums) {
int count = 0;
for(int e : nums){
if( Integer.toString(e).length() % 2 == 0) count++;
}
return count;
}
}